A) \[=\Delta \,E{}^\circ \]
B) \[>\Delta \,E{}^\circ \]
C) \[=zero\]
D) \[<\Delta \,E{}^\circ \]
Correct Answer: B
Solution :
We know that \[\Delta H{}^\circ =\Delta E{}^\circ +\Delta {{n}_{g}}RT\] For the reaction \[\Delta {{n}_{g}}=4-7=-\,3\] \[\therefore \,\,\,\,\,\,\,\,\,\Delta H{}^\circ = \Delta E{}^\circ -\Delta n{{\,}_{g}}RT\,\, \left[ \because \,\Delta {{n}_{g}} = negative \right]\] i.e., \[\Delta H{}^\circ <\Delta E{}^\circ \]You need to login to perform this action.
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