A) 40 lakh
B) 80 lakh
C) 96 lakh
D) 192 lakh
Correct Answer: C
Solution :
The maximum distance upto which TV transmission can be received, \[d=\sqrt{2\,hR}\] \[=\,\,\,\sqrt{2\times 80\times 6.4\times 1{{0}^{6}}}\] \[=\,\,\,32\,\,\times \,\,1{{0}^{3}}m\,\,=\,\,32\,\,km\] \[\operatorname{How} maximum are covered =\pi {{d}^{2}}\] \[=\,\,3.14\times {{\left( 32 \right)}^{2}}\] \[=\,\,\,3215.36\,\,\approx \,\,3200\,\,k{{m}^{2}}\] \[\therefore \,\,\,Population covered = 3200 \times 3000 = 96 lakh\]
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