A) \[\frac{\omega M}{M+m}\]
B) \[\frac{\omega (M-2m)}{M+2\,m}\]
C) \[\frac{\omega M}{M+2\,m}\]
D) \[\frac{\omega (M+2m)}{M}\]
Correct Answer: C
Solution :
As masses are added to the ring gently, there will be no torque and angular momentum will be conserved \[l\omega =l'\omega '\] \[\Rightarrow \,\,\,\,\,\,\,\,\,M{{R}^{2}}\omega \,\,=\,\,\left( M{{R}^{2}}+2m{{R}^{2}} \right)\omega '\] \[\Rightarrow \,\,\,\,\,\,\,\,\,\,\,\omega '=\frac{M\omega }{M+2m}\]You need to login to perform this action.
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