A) \[V\propto \frac{1}{r}\]
B) \[V=r\]
C) \[V\propto \frac{1}{{{r}^{2}}}\]
D) \[V\propto {{r}^{0}}\]
Correct Answer: D
Solution :
At an internal point \[(r<R)\] in a charged conducting sphere \[{{V}_{in}}={{V}_{surface}}\,\,=\,\,\frac{q}{4\pi {{\varepsilon }_{0}}R}=\,\,cons\tan t\] \[\therefore \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,V\propto {{r}^{0}}\]You need to login to perform this action.
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