A) triangular planar
B) tetrahedral and triangular planar respectively
C) tetrahedral
D) angular and triangular planar respectively
Correct Answer: A
Solution :
Structure of \[NO_{3}^{-}\] is \[H=\frac{V+M-C+A}{2}=\frac{5+1}{2}=\frac{6}{2}=3\] \[Hybridisation = s{{p}^{2}}\] \[\operatorname{Shape} = triangular planar\] Structure of \[CO_{3}^{-\,\,-}\] is \[H=\frac{V+M-C+A\text{ }}{2}\,\,=\,\,\frac{4+2}{2}\,\,=\,\,3\] \[Hybridisation = s{{p}^{2}}\] \[\operatorname{Shape} = triangular planar\]You need to login to perform this action.
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