A) \[2\,\,Mg\,\,sin\,\theta \]
B) \[\frac{1}{2}\,\,Mg\,\,sin\,\theta \]
C) \[\frac{2}{3}\,Mg \sin \,\theta \]
D) \[\frac{3}{2}\,Mg \sin \,\theta \]
Correct Answer: B
Solution :
The FBD of both the block is shown For 1st block, \[\operatorname{T}\,\,=\,\,Ma\] ... (i) For 2nd block, \[\operatorname{Mg}\,\,sin\,\,\theta -T=Ma\] ... (ii) From Eqs. (i) and (ii) \[2T=Mg\,\sin \,\theta \,\,\,\Rightarrow \,\,\,\,T=\frac{Mg\,\sin \,\theta }{2}\]You need to login to perform this action.
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