A) \[\frac{F}{{{M}_{1}}}\]
B) \[\frac{F-{{M}_{1}}\,a}{{{M}_{2}}}\]
C) \[\frac{F}{{{M}_{2}}}\]
D) None of these
Correct Answer: B
Solution :
Force acting on mass \[{{M}_{1}}\,\,is\,\,f={{M}_{1}}a\] Mass \[{{M}_{1}}\] will pull mass \[{{M}_{2}}\] towards left with a force \[\operatorname{F}={{M}_{1}}a\] Net force acting on mass \[{{\operatorname{M}}_{2}}\,\,=\,\,F-f=F-{{M}_{1}}-a\] \[\therefore \] Acceleration of mass \[{{M}_{2}}=\frac{F-{{M}_{1}}a}{{{M}_{2}}}\]You need to login to perform this action.
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