A) haemophilia
B) boys haemophilia
C) girls
D) normal
Correct Answer: D
Solution :
When a haemophilia man \[({{X}^{h}}Y)\] marries a normal woman (XX), produces carrier girls \[(X{{X}^{h}})\] and normal boys (XY), i.e. all their off springs will be normal.You need to login to perform this action.
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