A) 1
B) 2
C) 3
D) 0.1
Correct Answer: B
Solution :
Molar mass of \[\operatorname{HC}l = 36.5\] Concentration of \[HCl=\frac{0.365}{36.5}=1\times {{10}^{-\,2}}\,mol\,\,{{L}^{-\,1}}\] HCl is a strong acid \[\therefore \,\,\,\,\,\,\,\,\,\,\,\,\,pH\,=\,\,-\log \,[{{H}^{+}}]\] \[=\,\,-log1{{0}^{-}}^{2}\] \[=\,\,\,\,-1\times -\,2=2\]You need to login to perform this action.
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