A) \[84.95 %\]
B) \[45.64%\]
C) \[15.05 %~\]
D) \[44.36\,%\]
Correct Answer: C
Solution :
According to valency concept of \[3\,F{{e}^{2+}}\] will be replaced by\[2F{{e}^{3+}}\]. Total loss of iron from one mole of FeO \[=\,\,1-0.93=0.07\] Total \[{{\operatorname{Fe}}^{3+}}\] present in one molecule of FeO is \[2\times 0.07=0.14\] Total number of Fe (II) and Fe (III) present in one molecule of \[\operatorname{FeO} =0.93\] \[% \,of\, Fe(III)\,\,=\,\,\frac{0.14}{0.93}\times 100\]\[=\,\,\,15.05\,%\]You need to login to perform this action.
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