A) 4.31
B) 4.13
C) 8.62
D) 5.0
Correct Answer: A
Solution :
\[\operatorname{Given} molality = 5.0 m\]i.e., 5.0 moles of acetic acid is dissolved in 1000 g of solvent. Weight of 5 mole of acetic acid \[=\,\, 5 \times 60 = 300 g\] Therefore, weight of solution \[=\,\,1000 + 3000\]\[=\,\,\,1300g\] \[\operatorname{Volume} of this solution =\,\,\frac{1300}{1.12}\]\[=\,\,\,1160\,\,mL\] \[\operatorname{Molarity} = \frac{moles}{liter} = \frac{5}{1160}\times 1000 = 4.31\]You need to login to perform this action.
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