A) unchanged
B) halved
C) doubled
D) quadrupled
Correct Answer: D
Solution :
As, fringe width \[\beta =\frac{D\lambda }{d}\]where, \[\operatorname{d}= separation between slits\] \[\operatorname{D} =distance\,\,between slits and the screen.\] when d is halved and D is doubled. Consider \[\operatorname{d}=\,\,\frac{l}{2}x\] \[\operatorname{D}=2x\] Thus, \[\beta =\frac{2\times \lambda }{\frac{1}{2}\times }=4\,\lambda \] So, fringe width p will become four times.You need to login to perform this action.
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