A) I and II are correct
B) II and III are correct
C) I, II and III are correct
D) All are correct
Correct Answer: D
Solution :
This is due to wide space occupied by ?electron density which pushes both \[\operatorname{C}\,-C{{H}_{3}}\] bond to reduce \[\operatorname{Cl}-C-C{{H}_{3}}\] bond angle. \[O-I-F\] bond angle is also less than \[90{}^\circ \] in \[IOF_{4}^{\Theta }\] due to lone pair on I-atom. \[\operatorname{SeOC}{{l}_{2}}\] has \[\operatorname{Cl}-Se-Cl\] bond angle less than \[\operatorname{Cl}-Se-O\] due to re-electron. \[\operatorname{POC}{{l}_{3}}\] has tetrahedral structure due to presence of \[\pi -bond\] because if this \[\pi -bond\] is not.You need to login to perform this action.
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