A)
B) \[C{{H}_{3}}CH=C{{H}_{2}}\,\,\xrightarrow{NaN{{H}_{2}}}\]
C) \[2C{{H}_{3}}C{{H}_{2}}\,-\,Cl\,\,\,\,\xrightarrow{N{{H}_{3}}}\]
D)
Correct Answer: A
Solution :
\[2\,C{{H}_{2}}C{{H}_{2}}\,Cl\,\,\xrightarrow{N{{H}_{3}}}\,\,{{(C{{H}_{3}}C{{H}_{2}})}_{2}}NH\] 
But d will not produce an amine
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