2. Sample Papers
  3. NEET

NEET Sample Paper NEET Sample Test Paper-78

  • question_answer
    Molarity (M) of aqueous solution of acetic acid having density 1.12 g/mL and molality 5.0 m is

    A)  4.31                

    B)  4.13                    

    C)  8.62                            

    D)  5.0

    Correct Answer: A

    Solution :

    \[\operatorname{Given} molality = 5.0 m\]i.e., 5.0 moles of acetic acid is dissolved in 1000 g of solvent. Weight of 5 mole of acetic acid \[=\,\, 5 \times  60 = 300 g\] Therefore, weight of solution \[=\,\,1000 + 3000\]\[=\,\,\,1300g\] \[\operatorname{Volume} of this solution =\,\,\frac{1300}{1.12}\]\[=\,\,\,1160\,\,mL\] \[\operatorname{Molarity} = \frac{moles}{liter} = \frac{5}{1160}\times  1000 = 4.31\]


You need to login to perform this action.
You will be redirected in 3 sec spinner