A) 16 ml
B) 4 ml
C) 8 ml
D) 2 ml
Correct Answer: A
Solution :
By diagram \[T\,cos\,\theta \,\,=\,\,mg\] ... (i) \[T\,\sin \,\theta \,\,=\,\,\frac{m{{v}^{2}}}{r}\] \[\Rightarrow \,\,\,\,\,\,\,\,\operatorname{v} =\omega r\,\,\,\Rightarrow \,\,\,T \times \,\,\frac{r}{l}\,\,=\,\,m{{\omega }^{2}}r\] \[\Rightarrow \,\,\,~\,\,\,\,\,T=m{{\omega }^{2}}l\] \[\left( \because \,\,\,\,\,\sin \,\,\theta \,\,=\,\,\frac{r}{l} \right)\] \[=\,\,\,\,m{{\left( 2\pi \times \frac{2}{\pi } \right)}^{2}}l\] \[\operatorname{T}\,\,=\,\,16\,ml\]You need to login to perform this action.
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