A)
B)
C)
D)
Correct Answer: A
Solution :
As the block rises to the same height in all the four four cases, from conservation of energy, speed of the block at highest point will be same in all four cases say it is VQ. Equation of motion will be \[N+mg=\frac{mv_{0}^{2}}{R}\] or \[N=\frac{mv_{0}^{2}}{R}-mg\] R (the radius of curvature) in first case is minimum \[\therefore \] Normal reaction N will be maximum in first case.You need to login to perform this action.
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