2. Sample Papers
  3. NEET

NEET Sample Paper NEET Sample Test Paper-79

  • question_answer
    Least count of a stop watch is\[\frac{1}{2}\,\,s\]. The time of 30 oscillations of a pendulum is measured to be 40 s. The percentage error in measurement of time is

    A)  \[0.5\,%\]                     

    B)  \[1\,%\]

    C)  \[1.67\,\,%\]                 

    D)  None of these

    Correct Answer: C

    Solution :

    Percentage error in measuring time period \[T=\frac{\Delta T}{T}\times 100\] \[=\,\,\,\frac{\frac{1}{2}}{30}\times 100\] \[=\,\,\,\,1.67\,%\]


You need to login to perform this action.
You will be redirected in 3 sec spinner