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NEET Sample Paper NEET Sample Test Paper-79

  • question_answer
    The maximum number of possible interference maxima for slit-separation equal to twice the wavelength in Young's double slit experiment is

    A) infinite             

    B) five                  

    C) three               

    D) zero

    Correct Answer: B

    Solution :

    For possible interference maxima of the screen, then, condition is \[\operatorname{d}\,\,sin \theta \,\,=\,\,n\lambda \]                 ... (i) Given, \[\operatorname{d} =slit width =2\,\lambda \] \[\therefore \,\,\,\,\,\,\,\,\,\,2\lambda  \sin \,\,\theta  \,=\,\,n\,\lambda \] or           \[2\,\,sin\,\,\theta \,\,=\,\,n\] The maximum value of sin 6 is 1, hence \[n=2\times \,\,1=2\] Thus, Eq. (i) must be satisfied by 5 integers values i.e., -2, -1, 0, 1, 2 hence the maximum number of possible interference maxima is 5


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