A) Only A
B) Only B
C) Only C
D) All of these
Correct Answer: C
Solution :
\[\operatorname{Maximum} value of efficiency\,\,h=\,\,1-\frac{{{T}_{2}}}{{{T}_{1}}}\] \[=\,\,1-\frac{300}{500}=\frac{2}{5}\] \[\eta =\frac{W}{{{Q}_{1}}}\] \[W=\eta {{Q}_{1}}=\frac{2}{5}\times 1000\,\,cal\] \[=\,\, 400 \times 4.2 J =16803\]You need to login to perform this action.
You will be redirected in
3 sec