A) 486 J
B) 972 J
C) 1944 J
D) None of these
Correct Answer: A
Solution :
Let velocity of 12 kg block is v, then by linear momentum conservation \[30\times 0=12\times v+18\times 6\] \[\operatorname{v}=-\,9m/s\] (- ve sign indicates direction of velocity) So, kinetic energy of 12 kg mass \[=\,\,\,\,\frac{1}{2}\,m{{v}^{2}}\] \[=\,\,\,\,\frac{1}{2}\,\times 12\times {{(9)}^{2}}\] \[=\,\,\,486\,J\]You need to login to perform this action.
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