A) \[1.8\,\,\times 1{{0}^{-\,3}}\]
B) \[1.8\,\,\times 1{{0}^{-\,6}}\]
C) \[1.8\,\,\times 1{{0}^{-\,9}}\]
D) \[1.8\,\,\times 1{{0}^{-\,12}}\]
Correct Answer: B
Solution :
As, \[R=\rho \frac{I}{A}\] and \[V=IR=I\,\left( \frac{\rho l}{A} \right)\] Now, electric field \[E=\frac{V}{I}=\frac{\rho l}{A}=\frac{0.1\times (1.8\,\,\times \,\,{{10}^{-\,8}})}{{{10}^{-\,3}}}\] \[=\,\,\,1.8 \times \,\,{{10}^{-\,}}^{6}\]You need to login to perform this action.
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