question_answer

The compound \[{{[Ni\,{{(CN)}_{4}}]}^{2\,-}}\] is a complex and diamagnetic in nature. Then, the structure of \[{{[Ni\,{{(CN)}_{4}}]}^{2\,-}}\] is

A)  tetrahedral                   

B)  square planar

C)  sea-saw           

D)  trigonal monopyramidal

Correct Answer: A

Solution :

Structure of \[{{\left[ Ni{{(CN)}_{4}} \right]}^{2\,-}}\] Oxidation state of Ni in \[\left[ Ni {{\left( CN \right)}_{4}} \right]\] is + 2 Electronic configuration of \[N{{i}^{2+}}\,\,=\,\,\left[ Ar \right]3{{d}^{8}}\,4{{s}^{0}} 4{{p}^{0}}\,in {{\left[ Ni {{\left( CN \right)}_{4}} \right]}^{2}}^{-}\] \[Structure = square planar\]