A) \[{{B}_{2}}{{O}_{3}},\text{ }B{{O}_{2}},\text{ }and\text{ }BO\]
B) \[{{B}_{2}}{{O}_{3}},\text{ }{{B}_{2}}{{O}_{2}},\text{ }and\text{ }BO\]
C) \[{{B}_{2}}{{O}_{3}},\text{ }{{B}_{2}}{{O}_{3}},\text{ }and\text{ }{{B}_{2}}{{O}_{3}}\]
D) \[BO,\text{ }B{{O}_{2}},\text{ }and\text{ }{{B}_{2}}{{O}_{3}}\]
Correct Answer: C
Solution :
As B is a powerful reducing agent reduces \[C{{O}_{2}}\], NO and \[\operatorname{Si}{{O}_{2}}\]. B replaces C, Si and N from \[C{{O}_{2}},\,\,\operatorname{Si}{{O}_{2}}\] and NO respectively.You need to login to perform this action.
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