A) 3 g
B) 1.5 g
C) 0.75 g
D) None of these
Correct Answer: C
Solution :
Number of half-lives \[n=\frac{7200}{2400}\,\,=\,\,3\] \[\therefore \,\,\,Amount\,\,of\,\,C-14\,\,left\,\,=\,\frac{6g}{{{(2)}^{n}}}=\frac{6}{{{2}^{3}}}\] \[=\,\,\frac{6}{8}=0.75\,g\]You need to login to perform this action.
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