A) 8.3 A
B) 6.8 A
C) 4.9 A
D) 2.0 A
Correct Answer: D
Solution :
In the given circuit resistance \[{{\operatorname{R}}_{2}}\,\,and\,\,{{R}_{3}}\] are in series (Fig. I) So, equivalent resistance between them is \[{{R}_{2}}+{{R}_{3}}=\,\,6+6=12\,\,\Omega \] Which is in parallel with \[{{R}_{1}}=3\,\,\Omega \] So, equivalent resistance between A and B is \[{{R}_{AB}}=\frac{3\times 12}{3+12}=\frac{36}{15}\] Using Ohm?s law, \[I=\frac{V}{{{R}_{AB}}}=\frac{48}{36/15}\] \[=\,\,2\,A\]You need to login to perform this action.
You will be redirected in
3 sec