A) \[21.98 J{{K}^{-1}} {{W}^{-1}}\]
B) \[-\,21.98 J{{K}^{-1}} {{W}^{-1}}\]
C) \[-\,21.98 J{{K}^{-1}}\]
D) \[+\,21.98 J{{K}^{-1}}\]
Correct Answer: A
Solution :
We know that \[\Delta {{S}_{fus}}=\frac{\Delta {{H}_{fus}}}{{{T}_{m}}}=\frac{6000\,J}{273\,K}\,mo{{l}^{-\,1}}\] \[=\,\,\,21.98\,\,J{{K}^{-}}^{1}mo{{l}^{-1}}\]You need to login to perform this action.
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