A) + 6 and + 7 respectively
B) + 7 and + 6 respectively
C) + 7 and + 7 respectively
D) + 6 and + 6 respectively
Correct Answer: B
Solution :
Oxidation state of Mn in \[\operatorname{KMn}{{O}_{4}}\] can be determined as Let oxidation number of Mn in \[MnO_{4}^{-}\] is x \[\operatorname{x} +4\times \left( -\,2 \right)=-1, \,x=+7\] Let oxidation number of Cr in \[C{{r}_{2}}O_{7}^{-\,-}\] is x \[2x+7\times \left( -\,2 \right)=-\,2\] \[x=\frac{12}{2}\] \[=\,\,+\,6\]You need to login to perform this action.
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