A) \[2.88\]
B) \[3.6\]
C) \[4.0\]
D) \[1.0\]
Correct Answer: A
Solution :
For \[0.1\text{ }M\] acetic acid or \[C=0.1\,M{{L}^{-1}}\] \[{{K}_{a}}=1.74\times {{10}^{-5}}\] According to ostwald dilution formula \[[{{H}^{+}}]=\sqrt{{{K}_{a}}.C}\] \[=\sqrt{1.7\times {{10}^{-5}}\times 0.1}\] \[=\sqrt{0.017\times {{10}^{-4}}}\] \[pH=-{{\log }_{10}}[{{H}^{+}}]\] \[=-{{\log }_{10}}\left[ \sqrt{0.017\times {{10}^{-4}}} \right]\] \[pH=2.88\].You need to login to perform this action.
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