A) 3215 year
B) 6216 year
C) 4258 year
D) 2129 year
Correct Answer: C
Solution :
\[K=\frac{0.693}{{{t}_{{\scriptstyle{}^{1}/{}_{2}}}}}=\frac{0.693}{5770}=1.2\times {{10}^{-4}}yea{{r}^{-1}}\] \[{{N}_{0}}=100,\] \[{{N}_{N=60}}=100,\] \[t=\frac{2.303}{K}\log \frac{{{N}_{0}}}{N}\] \[=\frac{2.303}{1.2\times {{10}^{-4}}}\log \frac{100}{60}=4258year\]You need to login to perform this action.
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