A) \[{{I}_{0}}\]
B) \[2{{I}_{0}}\]
C) \[3{{I}_{0}}\]
D) \[4{{I}_{0}}\]
Correct Answer: C
Solution :
\[{{I}_{0}}={{I}_{dia}}=\frac{{{I}_{cm}}}{2}\] \[{{I}_{t\arg et}}={{l}_{cm}}+m{{R}^{2}}\] (from the parallel axis theorem) \[=\frac{1}{2}m{{R}^{2}}+m{{R}^{2}}\] \[=3{{\left( \frac{1}{2}mR \right)}^{2}}\] (Moment of inertia of a ring, about any of its diameters is \[\frac{M{{R}^{2}}}{2}\] ) \[=3I_{0}^{2}\]You need to login to perform this action.
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