A) \[\theta ={{\tan }^{-1}}\left( \frac{a}{g} \right)\]
B) \[\theta ={{\tan }^{-1}}\left( \frac{g}{a} \right)\]
C) \[\theta ={{\sin }^{-1}}\left( \frac{a}{g} \right)\]
D) \[\theta ={{\cos }^{-1}}\left( \frac{g}{a} \right)\]
Correct Answer: A
Solution :
From the figure \[\tan \theta =\frac{ma}{mg}=\frac{a}{g}\] \[\Rightarrow \] \[\theta ={{\tan }^{-1}}\left( \frac{a}{g} \right)\]You need to login to perform this action.
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