A) \[1.51\]
B) \[13.6\]
C) \[40.8\]
D) \[122.4\]
Correct Answer: D
Solution :
For lithium, \[\varepsilon =-{{Z}^{2}}\times 13.6eV\] \[=-9\times 13.6eV=-122.4eV\] So, ionization energy \[=+122.4eV\]You need to login to perform this action.
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