A) \[1250\text{ }K\]
B) \[500\,K\]
C) \[750\text{ }K\]
D) \[1000\text{ }K\]
Correct Answer: C
Solution :
\[\frac{1}{2}{{X}_{2}}+\frac{3}{2}{{Y}_{2}}\xrightarrow{{}}X{{Y}_{3}}\] \[\Delta {{S}_{reaction}}={{S}_{product}}-{{S}_{r\text{eactant}}}\] \[\Delta {{S}_{reaction}}=50-\left( \frac{3}{2}\times 40+\frac{1}{2}\times 60 \right)\] \[=-40\,Jmo{{l}^{-1}}\] \[\Delta G=\Delta H-T.\Delta S\] At equilibrium, \[\Delta G=0\] \[\Delta H=T\Delta S\] \[T=\frac{\Delta H}{\Delta S}=\frac{30\times {{10}^{3}}}{40}=750\,K\]You need to login to perform this action.
You will be redirected in
3 sec