A) \[2\,\,\times \,\,{{10}^{-}}^{5}\]
B) \[8\,\,\times \,\,{{10}^{-}}^{5}\]
C) \[9\,\,\times \,\,{{10}^{-}}^{5}\]
D) \[1\,\,\times \,\,{{10}^{-}}^{5}\]
Correct Answer: B
Solution :
\[\underset{Acidic\,\,red}{\mathop{HIn}}\,\,\,\xrightarrow{{}}\,\,{{H}^{+}}+\underset{Basic\,\,blue}{\mathop{I{{n}^{-}}}}\,\] \[{{K}_{a}}=\frac{[{{H}^{+}}][I{{n}^{-}}]}{[HIn]}\] When \[75\,%\] blue and \[25\,%\] red, then \[[{{H}^{+}}]=3\times {{10}^{-\,5}}\times \frac{25}{75}=1\times {{10}^{-\,5}}\] \[\therefore \,\,\,Change\,\,in\,\,[{{H}^{+}}]\,\,=\,\,9\times 10{{~}^{-\,5}}-1\times 1{{0}^{-}}^{8}\times 1{{0}^{-\,5}}\]You need to login to perform this action.
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