A) \[10{}^\circ \]
B) \[20{}^\circ \]
C) \[5{}^\circ \]
D) None of these
Correct Answer: A
Solution :
Dispersion without deviation, \[\Rightarrow \,\,\,\,\,\,\,\,{{S}_{1}}+{{S}_{2}}=0\] \[\Rightarrow \,\,\,\,\,\,\,(\mu -1)\,{{A}_{1}}+\,\,({{\mu }_{2}}-1)\,{{A}_{2}}=0\] \[\Rightarrow \,\,\,\,\,\,\,\,\,{{A}_{2}}=\frac{-({{\mu }_{1}}-1)}{({{\mu }_{2}}-1)}\,{{A}_{1}}\] Substituting values \[{{A}_{2}}=\frac{-(1.5-1)\,15{}^\circ }{(1.75-1)}\,\,=\,\,-10{}^\circ \] \[\left| {{A}_{2}} \right|\,\,=\,\,10{}^\circ \] Negative sign indicates the second prism must be joined in opposition.
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