NEET Sample Paper NEET Sample Test Paper-80

  • question_answer
    If two SHM's with same time period and same amplitudes are acting together in perpendicular directions with a phase difference of \[\pi /2\], then the motion will be

    A) straight motion

    B) circular motion

    C) elliptical motion            

    D) None of these

    Correct Answer: B

    Solution :

    Assume SHM are acting in x and y direction then, according to question \[\operatorname{x}\,\,=\,\,a\,\,sin\,\omega t\] \[\operatorname{y} =a sin\left( \omega t + \pi /2 \right)= a cos\,\omega t\] Now, \[{{\operatorname{x}}^{2}}+ {{y}^{2}}= {{a}^{2}}\,si{{n}^{2}}\,\omega t+ {{a}^{2}}\,co{{s}^{2}}\omega t\] \[{{\operatorname{x}}^{2}}+ {{y}^{2}}= {{a}^{2}}\,(si{{n}^{2}}\,\omega t+ {{a}^{2}}\,co{{s}^{2}}\omega t)\] \[{{\operatorname{x}}^{2}} +{{y}^{2}} ={{a}^{2}}\] Which is equation of circle.


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