A) \[{{\tan }^{-}}^{1}\,\left( 0.5 \right)\]
B) \[{{\tan }^{-}}^{1}\,\left( \sqrt{2} \right)\]
C) \[45{}^\circ \]
D) None of these
Correct Answer: D
Solution :
Here, Force, \[\operatorname{F} = 49 N\] Normal reaction, \[\operatorname{N} = mg= 10 \times 9.8= 98 N\] If h is coefficient of friction, then, \[\mu =\frac{F}{N}=\frac{49}{98}=0.5\] As. \[\tan \,\theta \,\,=\,\,\mu \] \[\Rightarrow \,\,\,\,\,\,\,\,\,\,\,\,\,\tan \theta =\,\,0.5\] \[\Rightarrow ~\,\,\,\,\,\,\,\,~\theta \,\,=\,\,ta{{n}^{-}}^{1}\,\left( 0.5 \right)\]
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