A) 222 s
B) 444 s
C) 602 s
D) 301 s
Correct Answer: B
Solution :
Given, \[\operatorname{K}\,\,=\,\,1.15\,\,\times \,\,1{{0}^{-\,3}}\,{{s}^{-1}}\] We know that \[K=\frac{2.303}{t}\log \,\frac{{{[a]}_{0}}}{{{[a]}_{t}}}\] \[t=\frac{2.303}{K}\log \,\,\left( \frac{5}{3} \right)\] \[=\,\,\,\frac{2.303}{1.15\times {{10}^{-\,3}}}\,(\log \,5-\log \,3)\] \[=\,\,\,\frac{2.303}{1.15\times {{10}^{-\,3}}}\,(0.698-0.477)\] \[=\,\,2\times 0.222\times 1{{0}^{3}}\] \[=\text{ }444\text{ }s\]You need to login to perform this action.
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