A) 156.00
B) 312.00
C) 78.00
D) 468.00
Correct Answer: A
Solution :
Weight of benzene \[=V\,\times d = 50 \times 0.879 g\] \[=43.95 g\] \[\operatorname{Weight} of compound = 0.643 g\] \[\Delta {{T}_{f}}\,\,=\,\,50.51-50.03=0.48\] \[\therefore \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\Delta {{T}_{f}}\,\,=\,\,{{K}_{f}}\times \,\,\frac{w}{M}\,\,\times \,\,\frac{1000}{W}\] \[0.48=5.12\times \frac{0.643}{M}\times \frac{1000}{43.95}\] \[\operatorname{M}\,\,=\,\,156.05 g\,mo{{l}^{-1}}\]You need to login to perform this action.
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