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NEET Sample Paper NEET Sample Test Paper-80

  • question_answer
    The equivalent weight of \[\operatorname{KMn}{{O}_{4}}\] in acidic medium will be

    A)  158                             

    B)  79

    C)  31.6                            

    D)  52.6

    Correct Answer: C

    Solution :

    Molecular mass of \[KMn{{O}_{4}}\] is \[38+56+64=158\] In acidic medium, \[KMn{{O}_{4}}\] is reduced to MnO \[\therefore \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{{\operatorname{Mn}}^{+7}}\,\xrightarrow{+\,\,5e}\,\,M{{n}^{+\,2}}\] \[\therefore  \,Equivalent weight of KMn{{O}_{4}} =\,\,\frac{M}{5} = \frac{158}{5} = 31.6\]


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