A) \[\frac{m{{v}^{2}}}{r}\,\,+\,\,mg\]
B) \[\frac{m{{v}^{2}}}{r}\,\,-\,\,mg\]
C) \[\frac{m{{v}^{2}}}{r}\]
D) mg
Correct Answer: A
Solution :
At point B, \[{{T}_{B}}-mg=\frac{m{{v}^{2}}}{r}\] \[\Rightarrow \,\,\,\,\,\,\,\,\,\,\,\,\,\,{{T}_{B}}\,\,=\,\,\frac{m{{v}^{2}}}{r}+mg\]You need to login to perform this action.
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