A) \[2y\,-3z{{t}^{2}}\]
B) \[\operatorname{x}+2y-3z{{t}^{2}}\]
C) \[\operatorname{x}+2yt-9{{t}^{2}}\]
D) None of these
Correct Answer: C
Solution :
As, distance, \[\operatorname{a} =\left( xt + y{{t}^{2}}- 3{{t}^{3}} \right)\] So, instantaneous speed \[=\,\,\,\frac{d(a)}{dt}\] \[=\,\,\,\frac{d}{dt}(xt+y{{t}^{2}}-3{{t}^{3}})\] \[= \,x + 2yt - 9{{t}^{2}}\]You need to login to perform this action.
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