NEET Sample Paper NEET Sample Test Paper-80

  • question_answer
    Using the given data, calculate heat of combustion of ethane
    Bond Bond energy
    \[C=C\] 619
    \[C-H\] 414
    \[O=O\] 499
    \[C=O\] 724
    \[O-H\] 660
     

    A)  \[+\,964 kJ mo{{l}^{-}}^{1}\]           

    B)  \[-\,964 kJ mo{{l}^{-}}^{1}\]

    C)  \[-\,3772 kJ mo{{l}^{-}}^{1}\]           

    D)  \[+\,3772 kJ mo{{l}^{-}}^{1}\]

    Correct Answer: B

    Solution :

    \[\Delta H = Sum of bond energy of products\] Sum of bond energy of reactants \[=\,\,\,[\Delta {{H}_{(c=c)}}+ 4\Delta {{H}_{(C-H)}} + 3\times \Delta {{H}_{O=O}}]\] \[-\,[4 \times  \Delta {{H}_{C\,=\,O}}+4\times \Delta {{H}_{O-H}}]\] \[= \left[ 619 + 4 \times  414 + 3 \times  499 \right] - \left[ 4 \times 724 +4 \times  460 \right]\]\[=\,\,\,-964kJ\,mo{{l}^{-}}^{1}\]


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