A) \[\frac{-d[{{I}_{2}}]}{dt}=\frac{-d[{{H}_{2}}]}{dt}=\,\frac{d[HI]}{dt}\]
B) \[\frac{d[{{H}_{2}}]}{dt}=\frac{d[{{I}_{2}}]}{dt}=\,\frac{d[HI]}{dt}\]
C) \[\frac{1}{2}\,\frac{d[{{H}_{2}}]}{dt}\,\,=\,\,\frac{1}{2}\,\frac{d[{{I}_{2}}]}{dt}=\,\frac{-d[H{{I}_{2}}]}{dt}\]
D) \[\frac{-2d[{{H}_{2}}]}{dt}\,\,=\,\,\frac{-2d[{{I}_{2}}]}{dt}=\,\frac{d[HI]}{dt}\]
Correct Answer: D
Solution :
According to rate law expression \[\frac{-d[{{H}_{2}}]}{dt}=\frac{-d[{{I}_{2}}]}{dt}=\frac{1}{2}\,\,\frac{d[HI]}{dt}\] On rearranging, we get \[\frac{d[HI]}{dt}=\frac{-\,2d\,[{{H}_{2}}]}{dt}=\,\,\frac{-\,2d[{{I}_{2}}]}{dt}\]
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