A) 158
B) 79
C) 31.6
D) 52.6
Correct Answer: C
Solution :
Molecular mass of \[KMn{{O}_{4}}\] is \[38+56+64=158\] In acidic medium, \[KMn{{O}_{4}}\] is reduced to MnO \[\therefore \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{{\operatorname{Mn}}^{+7}}\,\xrightarrow{+\,\,5e}\,\,M{{n}^{+\,2}}\] \[\therefore \,Equivalent weight of KMn{{O}_{4}} =\,\,\frac{M}{5} = \frac{158}{5} = 31.6\]You need to login to perform this action.
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