A) \[T=2\,K\]
B) \[T\,\,=\,\,12.18\,\,K\]
C) \[\operatorname{T}=24.36 K\]
D) \[\operatorname{T}\,\,=\,\,27.3\,\,K\]
Correct Answer: C
Solution :
\[\operatorname{PC}{{l}_{5}}\,\,PC{{l}_{3}}\,\,+\,\,C{{l}_{2}};\,\,\,\Delta {{n}_{g}}=\,\,1\] \[{{K}_{p}}={{K}_{c}}{{(RT)}^{\Delta \,n\,g}}\] \[\Rightarrow ~~~{{K}_{p}}\,\,=\,\,{{K}_{c}}RT'~~~~~\left\{ \because \,\,\,{{K}_{p}}=2{{K}_{c}} \right\}\] \[2{{K}_{c}}\,\,=\,\,{{K}_{c}}RT'\] \[RT=2\] \[T=\frac{2}{R}=\frac{2}{0.0821}=24.36\,K\]
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