A) \[0.7\,\,\sqrt{\frac{2}{3}}\,N\]
B) \[\frac{0.7\,\,\sqrt{3}\,}{2}N\]
C) \[0.7 \sqrt{3}\,\,N\]
D) \[\frac{0.7 \sqrt{2}}{3}\,\,N\]
Correct Answer: B
Solution :
Friction force, \[\operatorname{F} = \mu \,mg\,\,cos \theta \] \[=\,\,0.7\times 100\times {{10}^{-\,3}}\times 10\,cos\,\,30{}^\circ \] \[=\,\,0.7\times \frac{\sqrt{3}}{2}\] \[=\,\,\frac{0.7\,\sqrt{3}}{2}\,N\]You need to login to perform this action.
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