A) \[{{\tan }^{-1}}\,\left( \frac{3}{4} \right)\]
B) \[{{\tan }^{-1}}\,\left( \frac{4}{3} \right)\]
C) \[{{\tan }^{-1}}\,\left( \frac{5}{3} \right)\]
D) \[{{\sin }^{-1}}\,\left( \frac{4}{5} \right)\]
Correct Answer: C
Solution :
Polarising angle, \[\tan \,\,i=\frac{1}{\sin \,C}=\frac{1}{\sin \,\,{{\sin }^{-\,1}}\left( \frac{3}{5} \right)}\] \[\Rightarrow \,\,\,\,\,\,\tan \,\,i=\frac{5}{3}\Rightarrow i={{\tan }^{-\,1}}\,\left( \frac{5}{3} \right)\]
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