A) Sr
B) Be
C) Ra
D) Li
Correct Answer: B
Solution :
\[\operatorname{Be} \left( 1{{s}^{2}}2{{s}^{2}} \right)\] all the orbitals are filled and the size of Be is small, thus it does not allow excitation of electron and hence give no colour to the flameYou need to login to perform this action.
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